Math, asked by dd6217164, 5 months ago

The number of integers greater than 5000 that can be formed using 3, 4, 5, 6, 0 without repetition is:

Answers

Answered by shivamrdx
0

Answer:

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Step-by-step explanation:

Adding these up, there are 78 even numbers greater than 5000 that can be made with these digits. Originally Answered: How many numbers greater than 5000 can be formed using the digits 3, 4, 5, 6, and 7 without repetition of digits?

Answered by dolemagar
0

Step-by-step explanation:

first let's find out for 4 digit numbers greater than 5000.

5034

5036

5043

5046

5064

5063

5 followed by 0 gives six different numbers thus

there are 4 other numbers beside 5, left for combination

which gives us

6 different number× 4 combination

= 24 numbers

and moving to the next number greater than 5 we have 6 which also gives us 24 different numbers

well we can form 48 five digit numbers numbers

now let's find out 5 digit numbers greater than 5000.

and now for the other numbers excluding 0 in the beginning we can form

30456

30465

30546

30564

30645

30654

six different numbers

Thus, we have 4 other numbers for combination

which gives us = 6×4= 24

and same with 4 in the beginning

we have 24 numbers

with 5 we have 24 numbers and with 6 we have 24 numbers

so in total we have

48+24+24+24+24 = 144

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