Chemistry, asked by apereira8108, 1 year ago

The number of ions present in 1 ml of 0.1m cacl2 solution is

Answers

Answered by nagathegenius
0

Answer:

Explanation:

as cacl2 is a compound there will be atoms

so number of ions=no . of atoms * no. of ions

number of ions= 0.1/0.001*3

=3/0.01

=300

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