Question

The number of isomers of the compound C₂BrFCl is
(a) 3
(b) 4
(c) 5
(d) 6

Answer 1

a) is absolutely correct

Answer 2

$\huge\bold{He¥\: Mate}$

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$<b>$
➡️Correct Option -: A✔️✔️

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