Question

The number of lone pair of e electrons on the central atoms of H2O, ch4 ,NH3,
becl2 respectively are?

Answer 1

SoluTion :

✴ To Find :-

▪ The number of lone pairs of electrons on the central atoms of H2O, CH4, NH3 and BeCl2 are....

✴ Explanation :-

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$\boxed{\tt{\red{H_2O}}}$

• Hybridisation : SP3
• Bond pairs = 2
• Lone pairs = 2
• Central atom = Oxygen
• No. of valence electrons = 6

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$\boxed{\tt{\blue{CH_4}}}$

• Hybridisation : SP3
• Bond pairs = 4
• Lone pairs = 0
• Central atom = Carbon
• No. of valence electrons = 4

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$\boxed{\tt{\green{NH_3}}}$

• Hybridisation : SP3
• Bond pairs = 3
• Lone pairs = 1
• Central atom = Nitrogen
• No. of valence electrons = 5

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$\boxed{\tt{\orange{BeCl_2}}}$

• Hybridisation : SP2
• Bond pairs = 2
• Lone pairs = 0
• Central atom = Beryllium
• No. of valence electrons = 2

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