Question

The number of mole(s) of K2Cr207 that will be needed to react with two moles of oxalate ion in acidic medium is​

Answer 1

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B

31

The balanced chemical equation for the reaction between potassium dichromate and hydrogen sulphide is as given below:

K2Cr2O7+4H2SO4+3H2S→K2SO4+Cr2(SO4)3+7H2O+3S

1 mol of potassium dichromate reacts with 3 moles of hydrogen sulphide.

Hence, the number of moles of K2Cr2O7 that will be needed to react one mole of H2S in acidic medium is 31.

Explanation:

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