Question

the number of molecules in 100 ml of 0.02n h2so4

Answer 1

we know normality = molarity x n-factor
                      0.02 = M x 2
                molarity = 0.01

Number of moles of sulphuric acid = Molarity x volume(in litres)
                                                       = 0.01 x 0.1
                                                       = 0.001 moles

1 mole of sulphuric acid has Avogadro number(6 x 10²³) of molecules.

so, 0.001 moles of sulphuric acid contains 6 x 10²⁰ molecules

Answer 2

Molarity$=\frac{Normilaty}{n}$

$=\frac{0.02}{2}$

$=0.01$     [factor $number. of H^+ ion$, number of $H_2SO_4=2$]

Molarity $=\frac{Number of moles}{volume in lit}$

Number of moles$=volume \times molarity$

$=100\times 10^{-3}\times 0.01$

$=10^{-3}$

Number of molecules = Number of moles $\times 6.023 \times 10^{23}$

$=10^{-3}\times 6.023\times 10^{23}$

$=.6.023\times 10^(-3+23)$

$=6.023\times 10^{20}$

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