Question

The number of molecules in 22.4cm3 of ozone gas at STP is......
a) 6.022 X 1020 b) 6.022 X 1023
C) 22.4 X 1020
d) 22.4 X 1023
2) Thich of the following is heterocyclic compound 2​

Answer 1

Answer:

6.022×10^23

Explanation:

For explaination plz see the attached image.. surely it will help u ☺️

Answer 2

Given :

Volume of ozone gas = 22.4 cm³ = 22.4 ml = 22.4 × 10⁻³ L

To Find :

The number of molecules in 22.4cm³ of ozone gas at STP

Solution :

1 mole of any gaseous substance contains 6.022×10²³ molecules.

We know, 22.4 L of O₃ = 1 mole

So, 22.4 L of O₃ contains 6.022×10²³ molecules.

We are required to find the number of molecules present in 22.4 ml of O₃

22.4 L of O₃ contains 6.022×10²³ molecules

1 L of O₃ will contain $\frac{6.022 * 10^2^3}{22.4}$ molecules

22.4 ml of O₃ will contain $\frac{6.022 * 10^2^3}{22.4}$ × 22.4 × 10⁻³

                                       = 6.022 × 10²⁰

Therefore, 6.022 × 10²⁰ molecules are present in 22.4 cm³ of Ozone at STP.

∴ Option (a) 6.022 × 10²⁰ is correct.