Question

The number of moles of oxalate ions oxidised by one mole of MnO4- ion is=

Answer 1

just balance and use mole concept

Answer 2

Answer: The number of oxalate ions that are oxidized by 1 mole of permangante ion is 2.5 moles.

Explanation:

We are given:

Moles of permangante ions = 1 mole

The balanced chemical equation for the oxidation of oxalate ions by permanganate ion follows:

$2MnO_4^-+5C_2O_4^{2-}+16H^+\rightarrow 2Mn^{2+}+10CO_2+8H_2O$

By Stoichiometry of the reaction:

2 moles of permanganate ion oxidizes 5 moles of oxalate ion.

So, 1 mole of permangante ions will oxidize = $\frac{5}{2}\times 1=2.5moles$ of oxalate ion.

Hence, the number of oxalate ions that are oxidized by 1 mole of permangante ion is 2.5 moles.