Question

The number of moles of oxygen in 1L of air
containing 21% oxygen by volume, in standard
conditions, is
a) 0.186 mol b) 0.21 mol
c) 2.10 mol d) 0.0093 mol

Answer 1

Answer:

Explanation:

21% of 1 litre= 21/100 litre

Now moles= volume/22.4

So here

Moles of oxygen=(21/100) / 22.4

=0.93/100

= 0.0093 moles