The number of n digit numbers,no two consecutive digits being the same is
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Answer: n!
Solution: Assuming that no two consecutive digits are the same, the number of n digit numbers, is n!.
For example, 4! = 4.3.2.1
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There are {0,1,2,10}, 10 different digits of which 1
st
place is filled in 9 ways, 2
nd
place in 9 ways (since 0 can be included and first digit is not repeated) and so on n times.
Thus number of ways is =9×9×____=9
n
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