The number of numbers divisible by 3 that can be formed by four different even digits is
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Step-by-step explanation:
Since the number is divisible by 3, the sum of the digits should be multiple of 3.
∴∴ The digits can be 0,2,4,6or0,4,6,80,2,4,6or0,4,6,8
Hence the required no. of numbers = (4!−3!)+(4!−3!)=36(4!−3!)+(4!−3!)=36
Hope it helps you....
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