The number of numbers lying between 100 and 500 that are divisible by 7
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hey frnd.....
Here
a = 105
d = 7
l = 497
now we know that last term = a+(n-1) d
497 = 105 +(n-1)7
392 = (n-1) 7
56 = n-1
n = 57
so there are 57 number lying between 100 and 500 divisible by 7//
HOPE THIS HELP YOU ☺☺❤❤✌✌✌✌
Here
a = 105
d = 7
l = 497
now we know that last term = a+(n-1) d
497 = 105 +(n-1)7
392 = (n-1) 7
56 = n-1
n = 57
so there are 57 number lying between 100 and 500 divisible by 7//
HOPE THIS HELP YOU ☺☺❤❤✌✌✌✌
Anonymous:
ya... now i remember
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