Question

the number of ordered pair of integers(n,m) for which n^2-m^2=14 is

Answer 1

Hi ...dear....
here is your answer...!!.....

Given,
n^2-m^2=14...


(.n+m)(n-m) = 7*2..


see picture...!!!..
by solving equations we get...
..(m,n)= (9/2,5/2 ) or (9/2 , -5/2)...
hope it helped you!!
Regards Brainly Star Community
#shubhendu

Answer 2

Answer:

Can not be determined.

Step-by-step explanation:

Given,

$n^2-m^2=14$

$(n+m)(n-m)=14$

$(n+m)(n-m)=7\times 2$

Where, both n and m are integers,

⇒ n-m and n+m must be integers.

Also, n+m > n-m

Thus, by comparing,

n+m=7 and n-m = 2,

By adding the above equations,

2n=9 ⇒ n = 9/2 ( not possible ),

And, m = 7- 9/2= 5/2 ( not possible )

Hence, the values of m and n can not be determined.