Question

the number of oxygen atom in 20g of sulphur dioxide (So3) is the same as those present in X grams of ozone(O3) The atomic mass of sulphur and oxygen are 32g and 16g respectively find the value of x
please help ​

Answer 1

$\sf{No.\:of\:oxygen\:atoms \: in\: 20g\:of\:SO_3,\:we\:have,}$

$\sf{Molar \: mass \: of \: SO_3}$

= 32 + 3 x 16 = 80 g.

80 g of SO, have oxygen atoms is

$\sf{3 \times N_A}$

20 g of SO, have oxygen atoms

$\sf{ = \frac{3 \times N_A \times (20g)}{80g} = 0.75N_A}$

Mass of ozone having same no. of oxygen atoms,we have

$\sf{Molar \: mass \: ofO_3 = 3×16=48g}$

3×NA oxygen atoms are present in ozone

$\sf{ = (48g) \times \frac{10.75 \times N_A}{(3 \times N_A)} }$

= 12g

Thus, x = 12g

Answer 2

Answer:

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