Physics, asked by vishal7068, 11 months ago

The number of oxygen atoms present in 14.6 g
of magnesium bicarbonate [Mg(HCO3)}] is​

Answers

Answered by AAravRj
18

Answer:

molecular mass of magnesium bicarbonate = 146

no. of moles = given weight/moecular weight

                   =  14.6/146 =0.1                                                                              …...............(1)

       here, no. of moles of oxygen in magnesium bicarbonate = 16*3*2/16 = 6  …..............(2)

[from (1) and (2) ],

       0.1*6*NA =0.6 NA

So, the number of oxygen atoms present in 14.6 g of magnesium bicarbonate is 0.6 NA.

Explanation:

I hope it is help full for you.

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