The number of oxygen atoms present in 14.6 g
of magnesium bicarbonate [Mg(HCO3)}] is
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molecular mass of magnesium bicarbonate = 146
no. of moles = given weight/moecular weight
= 14.6/146 =0.1 …...............(1)
here, no. of moles of oxygen in magnesium bicarbonate = 16*3*2/16 = 6 …..............(2)
[from (1) and (2) ],
0.1*6*NA =0.6 NA
So, the number of oxygen atoms present in 14.6 g of magnesium bicarbonate is 0.6 NA.
Explanation:
I hope it is help full for you.
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