Math, asked by vandanadaryanani, 19 days ago

the number of pages of magazine A and B are 64 and 96 respectively. The space used for advertisement in magazine B is twice that

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Answered by surenderrawat0007
0

Answer:

a survey of 100 persons it was found that 28 read magazine A, 30 read magazine B, 42 read magazine C, 8 read magazines A and B, 10 read magazines A and C, 5 read magazines B and C and 3 read all the three magazines. Find how many read none of three magazines?

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Solution

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Correct option is A)

Step -1: Use different variables and set theory to define varibles.

Total number of persons =100

Number of persons who read magazineA=n(A)=28

Number of persons who read magazine B=n(B)=30

Number of persons who read magazine C=n(C)=42

Number of persons who read both magazine A and B =n(A∩B)=8

Number of persons who read both magazine B and C =n(B∩C)=5

Number of persons who read both magazine C and A =n(A∩C)=10

Number of persons who read all three magazine =n(A∩B∩C)=3

Total number of readers = 80

Step -2: Use the set formula to find the total number of people who read none of three magazines.

Number of people who do not read magazine are,

⇒n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B) −n(B∩C)−n(C∩A)+n(A∩B∩C)

⇒n(A∪B∪C)=28+30+42−8−5−10+3

Number of readers who read magazines are =80

So, number of readers who do not read any magazine are =100−80

=20

Hence, readers who read none of the magazines are 20.

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