the number of pages of magazine A and B are 64 and 96 respectively. The space used for advertisement in magazine B is twice that
Answers
Answer:
a survey of 100 persons it was found that 28 read magazine A, 30 read magazine B, 42 read magazine C, 8 read magazines A and B, 10 read magazines A and C, 5 read magazines B and C and 3 read all the three magazines. Find how many read none of three magazines?
Medium
Open in AppOpen_in_app
Solution
verified
Verified by Toppr
Correct option is A)
Step -1: Use different variables and set theory to define varibles.
Total number of persons =100
Number of persons who read magazineA=n(A)=28
Number of persons who read magazine B=n(B)=30
Number of persons who read magazine C=n(C)=42
Number of persons who read both magazine A and B =n(A∩B)=8
Number of persons who read both magazine B and C =n(B∩C)=5
Number of persons who read both magazine C and A =n(A∩C)=10
Number of persons who read all three magazine =n(A∩B∩C)=3
Total number of readers = 80
Step -2: Use the set formula to find the total number of people who read none of three magazines.
Number of people who do not read magazine are,
⇒n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B) −n(B∩C)−n(C∩A)+n(A∩B∩C)
⇒n(A∪B∪C)=28+30+42−8−5−10+3
Number of readers who read magazines are =80
So, number of readers who do not read any magazine are =100−80
=20
Hence, readers who read none of the magazines are 20.
Was this answer helpful?
upvote 85
downvote9
Similar questionsstar-struck
Find (A∪B)−C when A={a,b,c},B={d,e,g} and C={b,c,e}.