Question

The number of photons emitted per second by a 62W source of monochromatic light ofwavelength 4800 A° is n×10 power20 then n is please say the answer

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Answer 1

Answer:

Power of the source = 62 watt

Energy emitted in a second = 62 joules

So, number of photons emitted in a second =

hC

62λ

=

6.626×10

−34

×3×10

8

62×4800×10

−10

photons / sec

=1.4962×10

20

photons / sec

≈1.5×10

20

photons /sec