The number of photons of light of wave number 2.5 x 10^6 m^-1 necessary to provide 1J of energy are
Answers
Answered by
49
λ⁻¹=2.5×10⁶m⁻¹
E=hc/λ
=6.63×10⁻³⁴×3×10⁸×2.5×10⁶
=49.725×10⁻²⁰
for 1J of energy 1/49.725×10²⁰ photons required
=2.011×10¹⁸
E=hc/λ
=6.63×10⁻³⁴×3×10⁸×2.5×10⁶
=49.725×10⁻²⁰
for 1J of energy 1/49.725×10²⁰ photons required
=2.011×10¹⁸
Similar questions
Science,
7 months ago
English,
7 months ago
History,
7 months ago
Political Science,
1 year ago
Chemistry,
1 year ago