Question

The number of planks of dimensions (4m×5m×2m)that can be stored in a pit which is 40m long , 12m wide and 16m deep , is

Answer 1

TSA of the plank=2×(lb+BH+hl)
=2×(4×5+5×2+2×4)
=2×(20+10+8)
=2×38
=76 m²

volume of the pit=l×b×h
=40×12×16
=480×16
=7680m³

no of planks that can be fitted in the pit=7680/76
=101.05....

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Answer 2

Given,

Dimensions of a cuboidal pit:

Length = 40 m

Width = 12 m

Depth = 16 m

Dimensions of each plank:

Length = 5 m

Width = 4 m

Depth = 2 m

To find,

The number of planks that can be stored in the pit.

Solution,

We can simply solve this mathematical problem using the following process:

As per mensuration;

The volume of a cuboid

= length × breadth × height

{Statement-1}

Now, according to the question and statement-1;

The volume of the pit

= length × breadth × height

= (40m × 12m × 16m)

= 7680 m^3

And, the volume of each plank

= length × breadth × height

= 4m×5m×2m

= 40 m^3

So, the number of planks that can be stored in the pit

= (volume of the pit)/(volume of each plank)

= (7680 m^3)/(40 m^3)

= 192 planks

Hence, 192 planks can be stored in the pit.