Question

The number of polynomials present with 4 and -2 as zeros ​

Answer 1

Answer:

Probably 1

Hope I am correct.

Answer 2

$\huge {\bold {\pink {s0lUtion}}}$

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$\alpha + \beta = 4 + ( - 2) = 2 \\ \\ \alpha \beta = 4( - 2) = - 8$

$Therefore,$

$Polynomial$

${x}^{2} - ( \alpha + \beta )x + ( \alpha \beta ) \\ \\ {x }^{2} - (2)x + ( - 8) \\ \\ => {x}^{2} - 2x - 8$

$single \: polynomial$

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$\huge {\bold {\pink {Hope \: it \: helps}}}$