Question

The number of primary alkanols, secondary alkanols
and tertiary alkanols possible with the formula
C4H100 is given by the set :-
(1) 2, 1, 0
(2) 1, 2, 1
(3) 2, 1, 1
(4) 2, 1, 2​

Answer 1

Answer: (3)

Explanation:

1° → n-butanol and

isobutanol (2-methylpropan-1-ol)

2°→ secbutanol (butan-2-ol)

3°→ tertbutanol (2-methylpropan-2-ol)