Math, asked by pratishtharichu, 11 months ago

The number of real roots of the polynomial equation x⁴ – x² + 2x – 1 = 0 is
(A) 0
(B) 2
(C) 3
(D) 4

Answers

Answered by edison60
5

Answer:

There are 4 real roots

Step-by-step explanation:

As the degree of the polynomial is 4

Answered by sk940178
2

Answer:

4

Step-by-step explanation:

The number of roots of a polynomial equation is given by the degree of the polynomial.

Example:

(i) ax+b=0 is a polynomial equation with degree one. Hence, the equation will have one root.

(ii) ax²+bx+c=0 is a polynomial equation with degree two. Hence, the equation will have two roots.

(iii) ax³+bx²+cx+d=0 is a polynomial equation with degree three. Hence, the equation will have three roots and similarly

(iv) ax^{4}+bx³+cx²+dx+e =0 is a polynomial equation with degree four. Hence, the equation will have four roots.

In this case, the equation x^{4} -x^{2} +2x-1=0 is a 4 degree polynomial equation and hence it will have 4 roots.(Answer)

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