Question

The number of real solution of the equation |x-1|= -3 +x-x^2​

Answer 1

Answer:

Finding the roots of equation (1) is as shown below:

x2−2x+1=0

x2−x−x+1=0

x(x−1)−1(x−1)=0

x−1=0 and x−1=0

x=1 

Finding the roots of equation (2) is as shown below:

x=2a−b±b2−4ac

=2(1)−2±(2)2−4(1)(−1) 

=2−2±8 

=2−2±22 

=−1±2 

Therefore, x=1 and x=−1±2