The number of revolutions made by an electron per second in the third orbit of hydrogen atom is (in the first orbit of hydrogen atom, velocity = and radius = 0.53 å)
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Answer:
The number of revolutions made by an electron per second in the third orbit of hydrogen atom is 2.40758 x 10^14 cycles /sec
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at first, we have to find velocity of electron and then radius of orbit in which electron revolves around the nucleus.
from Bohr's theory,
m/s
where Z is atomic number and n is orbit number.
for 3rd orbit of H-atom,
Z = 1 and n = 3
so, v = 2.165 × 10^6 × 1/3
= 0.7217 × 10^6 m/s
again, radius of nth orbit, A°
for 3rd orbit for H-atom. n = 3 and z = 1
= 0.53 × 3²/1 A°
= 4.77 × 10^-10m
now, number of revolution made by an electron per second , f = v/2πr
= 0.7217 × 10^6/(2 × 3.14 × 4.77 × 10^-10
= 0.024 × 10^16 Hz
= 2.4 × 10¹⁴ Hz
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