the number of sides of two regular polygon is in the ratio 3:2and their interior angles are in the ratio 5:3 . find the number of sides
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Answer:
A =3/2
Explanation:
let the side of 1st polygon =3A
side of 2nd polygon =2A ,
but now according to question , we have
[ (3A-2)×180°/3A] /[ (2A-2)×180°/2A]=5/3
[(3A-2)×2A]/ [(2A-2)×3A] =5/3
(6A-4)/(6A-6)=5/3
18A-12 =30A-30 ,
30A -18A = -12 +30
30A-18A =12-30,
12A = 18
A =3/2
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