the number of six hit by gayle is double the number of fours hit by him.he scored 16 runs by running between the wickets. if his final score is 80 runs , find the number of four and sixes hit by him
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Let the no. of fours be x
no. of six be 2x
Runs scored by fours = 4x
Runs cored by sixes =2x ×6=12x
Now
12x +4x +16=80
16x=64
x=4
No. of fours =4
No.of sixes =8
no. of six be 2x
Runs scored by fours = 4x
Runs cored by sixes =2x ×6=12x
Now
12x +4x +16=80
16x=64
x=4
No. of fours =4
No.of sixes =8
basu007:
thank you so much .
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