the number of solution of equation ||x-2|-2|=1
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Step-by-step explanation:
Let us take 2 scenarios x>1, x<1 and x=2
x>1 then the equation is x^2+x-2=0, it has 2 solutions (-2, 1)
x<1 then the equation is x^2-x=0, it has 2 solutions (0,1)
x=1, the. The equation is x^2–1=0, it has 2 solutions (1, -1)
Total there are 6 solutions if we count repeat solutions, otherwise there are 3 solutions (-2,0,-1)
I hope it's helpful
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