Math, asked by manpreetsinghtherock, 1 year ago

The number of solutions of the equation
sec x/1-cosx=1/1-cos x in[0,2π] is equal to:

Answers

Answered by pinquancaro
8

Answer:

There is only one solution i.e. at x=0.

Step-by-step explanation:

Given : Expression \frac{\sec x}{1-\cos x}=\frac{1}{1-\cos x}

To find : The number of solutions of the equation  in [0,2π] ?

Solution :

Expression \frac{\sec x}{1-\cos x}=\frac{1}{1-\cos x}

First we solve the expression,

\frac{\sec x(1-\cos x)}{1-\cos x}=1

\sec x=1

From  [0,2π]  the sec x is 1 is only at 0.

So, \sec x=\sec 0

x=0

Therefore, There is only one solution i.e. at x=0.

Answered by wadhokarshweta
1

Answer:

No solution

Step-by-step explanation:

secx/1-cosx =1/cosx

For 1−cosx =0⇒cosx =1 ..(1)

For 1−cosx =0⇒cosx =1 ..(1)Gives secx=1⇒cosx=1 ...(2)

For 1−cosx =0⇒cosx =1 ..(1)Gives secx=1⇒cosx=1 ...(2)From (1) and (2) we get no solution

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