The number of solutions of the equation
x logx (1-x)2= 25 is
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Step-by-step explanation:
Given The number of solutions of the equation
x logx (1-x)2= 25 is
- We need to find the solution for the equation
- x^log (1 – x)^2 base x = 25
- By the property of log we have
- So b^log a base b = a
- Applying this we get
- (1 – x)^2 = 25
- So using (a – b)^2 = a^2 – 2ab + b^2 we get
- 1 – 2x + x^2 = 25
- x^2 – 2x = 24
- x^2 – 2x – 24 = 0
- x^2 – 6x + 4x – 24 = 0
- x(x – 6) + 4(x – 6) = 0
- (x – 6) (x + 4) = 0
- x = (6,-4)
- So the solution will be x = 6, - 4
Reference link will be
https://brainly.in/question/5041251
Answered by
0
Answer:
X=6,-4...
hope it helps you
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