Question

The number of solutions of x^2+|x-1|=1 is​

Answer 1

SOLUTION :

$\sf \: {x}^{2} + |x - 1| = 1$

$\implies \sf \: {x}^{2} + x - 2 = 0$

$\implies \sf {x}^{2} + 2x - x - 2 = 0$

$\implies \sf \: (x - 1)(x + 2) = 0$

$\implies \sf \boxed{ \sf{x = 1 \: \: or \: \: x = - 2}}$