The number of ten digit numbers that contain only 2 and 3 as its digit, but no any pairwise 3's
joins together, is
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Solution:
When exactly one 3′s are used, then numbers possible = 10 C 1
When exactly two 3′s are used, then numbers possible = 9 C 2
When exactly two 3′s are used, then numbers possible = 8 C 3
When exactly two 3′s are used, then numbers possible = 7 C 4
When exactly two 3′s are used, then numbers possible = 6 C 5
well use only 5 3's coz if we use more then the case is not possible
Adding all =143
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