Question

the number of terms in the expansion (a+b)^98-(a-b)^98

Answer 1

Answer:

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$(a + b) {}^{98} - (a - b) {}^{98 } = a {}^{98} - b {}^{98}$

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Answer 2

Answer:

49

Step-by-step explanation:

In the binomial expansion of (a+b)^98

→98C0.a^98 + 98C1.a^97.b + 98C2.a^96.b^2 + ............. + 98C98 b^98

While in the binomial expansion of (a-b)^98

→98C0.a^98 - 98C1.a^97.b + 98C2.a^96.b^2 - ............. + 98C98 b^98

So in total each each binomial expansion there are 98 terms each.

But when the 2nd expansion is subtracted from the first (as per the question) half of them cancel each other..

Thus remaining....

The no. of terms in the given expansion is 98/2 = 49 terms

Hope it helped u... All the best

It's an assured answer and not guessed