Math, asked by vibhadudile60, 11 months ago

the number of terms in the series 101+99+97+........+47 is ?

plz give with method

Answers

Answered by priyanka336

Step-by-step explanation:

Mark it as brainliest.and follow.

hope it helps

Attachments:

vibhadudile60: sorry but the number is not in my option

vibhadudile60: i think something went wrong

vibhadudile60: so plz try this one

vibhadudile60: i think the difference is not -2 its only 2

vibhadudile60: start from 47

priyanka336: I have made corrections..

priyanka336: u can check the options now

vibhadudile60: thank you very much

vibhadudile60: it really helped me

priyanka336: welcome.

Answered by siddhartharao77

Answer:

Step-by-step explanation:

Given Series is 101 + 99 + 97 + ... + 47.

Here,

First term a = 101

Common difference (d) = -2

Last term an = 47

Now,

an = a + (n - 1) * d

⇒ 47 = 101 + (n - 1) * (-2)

⇒ 47 = 101 - 2n + 2

⇒ 47 = 103 - 2n

⇒ -56 = -2n

⇒ n = 28

Hope it helps!

vibhadudile60: thank u very much this is the right answer thank you

siddhartharao77: Welcome..

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