Math, asked by naseehasahar12345, 6 months ago

The number of terms in the series 11, 15, 19,.....,211 is

Answers

Answered by Snapskg730

4

Answer:

d = 15-11 = 4

an = a + (n-1)d

211 = 11 + (n-1)4

211-11 = (n-1)4

200/4 = (n-1)

50 = n-1

50+1 = n

n = 51

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