Question

The number of terms of AP 5,9,13......185 is

Answer 1

$\bf\large\underline\pink{Solution:-}$

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$\bf\large\underline\red{Given:-}$

A. P is 5 , 9 ,13 , .... 185

Here first term = 5

Common difference = a2 - a1 = 9 -5 = 4

The A.p is 5 , 9 , 13 , ......., 181 , 185

We have find out the 9 th term from the end .

Now , rearrange the A. P

185 , 181 , ......, 13 , 9 , 5

First term = a = 185

Common difference = d = a2 - a1 = 181 - 185 = - 4

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n th term in an A. P = an = a + ( n - 1 ) d

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a = 185 ; d = -4 ; n = 9

9 th term = a9 = a + ( 9-1 ) d

= 185 + 8 × ( - 4 )

= 185 - 32

= 153

Therefore required 9 th term from the end = 153.

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Answer 2

Answer:

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