the number of two digit is 7 times the sum of its digit we 27 is subtracted from the number the digits is reverse find the number.
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The correct answer is
Let the unit place digit be x .
and tens place digit be y.
then,the no. formed = 10y+x
=(10y+x)= 7(x+y)
= 10y+x= 7x+7y
= 3y-6x= 0
= 3y= 6x
= y= 2x.........(i)
No. formed after reversed= 10x+y
10y+x-27= 10x+y
9y-9x= 27
y-x= 3
putting value of x from equation (i) in (ii)
2x-x= 3
x= 3
so ,y= 6
hence ,the no. obtained = 63
××××××××××××××××××××××××
Hope you enjoy
××××××××
The correct answer is
Let the unit place digit be x .
and tens place digit be y.
then,the no. formed = 10y+x
=(10y+x)= 7(x+y)
= 10y+x= 7x+7y
= 3y-6x= 0
= 3y= 6x
= y= 2x.........(i)
No. formed after reversed= 10x+y
10y+x-27= 10x+y
9y-9x= 27
y-x= 3
putting value of x from equation (i) in (ii)
2x-x= 3
x= 3
so ,y= 6
hence ,the no. obtained = 63
××××××××××××××××××××××××
Hope you enjoy
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