The number of unit cells present in one Mole of Nacl crystal are
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So , the molecular mass of NaCl is 23 + 35.5 =58.5 . NaCl occupies fcc structure i.e 4 atoms will constitute 1 unit cell.
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The mass of -Avogadro number of molecules- of NaCl is 58.5g.
Then, number of molecules in one gram = 6.022× 10^23 ÷ 58.5 = 1.03×10^22 molecules
As we found above that each unit cell contains 4 molecules of NaCl hence we can now easily find the number of unit cells containing 1.03×10^22 molecules = 1.03×10^22 ÷ 4 = 2.575×10^21 unit cells
So, 2.575×10^21 unit cells contains 1gm of NaCl molecules.
Then, number of molecules in one gram = 6.022× 10^23 ÷ 58.5 = 1.03×10^22 molecules
As we found above that each unit cell contains 4 molecules of NaCl hence we can now easily find the number of unit cells containing 1.03×10^22 molecules = 1.03×10^22 ÷ 4 = 2.575×10^21 unit cells
So, 2.575×10^21 unit cells contains 1gm of NaCl molecules.
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