Chemistry, asked by Umar9871, 1 year ago

The number of water molecules in 1 litre of water is

Answers

Answered by vipulyadav2003
68

Answer:

1000

One mole of water has a mass of 18 grams and a volume of 18 mL (as the density of water is 1 g per cm3). It contains Avogadro's number of molecules (6x 10^23). Thus 1 litre of water contains 1 / 18 x 1000 x 6 x 1^23. molecules......

Answered by RomeliaThurston
142

Answer: The number of water molecules in 1 L of volume is 3.345\times 10^{25}

Explanation:

To calculate mass of a substance, we use the equation:

\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}

We are given:

Density of water = 1 g/mL

Volume of water = 1 L = 1000 mL    (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{1000mL}\\\\\text{Mass of water}=1000g

To calculate the number of moles of compound, we use the equation:

Given mass of water = 1000 g

Molar mass of water = 18 g/mol

Putting values in above equation, we get:

\text{Moles of water}=\frac{1000g}{18g/mol}=55.55mol

According to mole concept:  

1 mole of compound contains 6.022\times 10^{23} number of molecules

So, 55.55 moles of water will contain = 55.55\times 6\times 6.022\times 10^{23}=3.345\times 10^{25} number of molecules.

Hence, the number of water molecules in 1 L of volume is 3.345\times 10^{25}

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