The number of wavelength in third orbit of h atom
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Radius of 3rd orbit = r = R(3)^2
= 9 R
[Here R = Radius of first orbit of hydrogen atom]
mvr = nh / (2 π)
h/(mv) = 2πr / n
λ = h / (mv) = 2π × 9R / 3
λ = 6πR
λ = 6 π × (0.529 Å)
λ = 9.97 Å
De-Broglie wavelength is 9.97 Å
i hope this will help you
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