the number of ways in which 15 mangoes can be equally divided among 3 students is
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Each student should get 5 mangoes so that it can be equal to all
aritribiswas:
Yea
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We couldn't care less what arrange the articles are in.
Getting mango 1, mango 2, and mango 3 would be the same as getting mango 3, mango 1, and mango 2.
You now and again hear this called "n pick r" or, in your concern, "12 pick 3."
It can be composed as 12C3.
The equation is nCr = n! /((n-r)! * r!) 12C3 = 12! /((12-3)! * 3!) 12C3 = 12! /(9! * 3!)
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