Math, asked by swathy08, 7 months ago

The number of ways in which six boys and six girls can be
seated at a round table so that no two girls sit together and
two particular girls do not sit next to a particular boy is
(a) 6! 4!
(b) 2.5! 4!
(C) 2.6! 4!
(d) 5! 4!​

Answers

Answered by cutiik
0

Answer:

Step-by-step explanation:

Total number of ways in which boys can sit in Alternative position

= 6!

Total ways=6!

So,6!*6!*2

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