Question

The number of workers employed month wise in the worksite of a construction company for 11 months is given below. 45 ,52, 56, 47, 53, 60, 45,40, 52, 48, 50 Find the mean and median of the given data​

Answer 1

$\huge{ \underbrace{ \text{Question}}}$

The number of workers employed month wise in the worksite of a construction company for 11 months is given below. 45 ,52, 56, 47, 53, 60, 45,40, 52, 48, 50 Find the mean and median of the given data

$\huge{ \underbrace{ \text{Answer}}}$

Given:-

The number of workers employed month wise in the worksite of a construction company for 11 months are:-

45 ,52, 56, 47, 53, 60, 45,40, 52, 48, 50

To Find:-

$\sf{ \rightarrow{the \: mean \: and \: the \: median \: of \: the \: data}}$

Solution:-

We know that,

Mean of a data:-

$\boxed{ \sf{ \blue{ \bold{m} = \frac{sum \: of \: the \: terms}{number \: of \: the \: terms} }}}$

According to the question,

$\sf{ \bold{m}} = \frac{45 + 52 + 56 + 47 + 53 + 60 + 45 + 40 + 52 + 48 + 50}{11}$

$\sf{ \bold{m}} = \frac{548}{11} \\ \\ \sf{ \bold{m}} = \orange{49.8182}$

Again,

Arranging the data, we find:-

40, 45, 45, 47, 48, 50, 52, 52, 53, 56, 60

We know that ,

Median of a data (if the number of the terms are in odd number)

$\boxed{ \sf{ \blue{ \bold{median} = \frac{n + 1}{2}th \: term}}}$

According to the question,

$\sf{ \bold{median}} = \frac{11 + 1}{2} th \: term \\ \\ \sf{ \bold{ = > median}} = \frac{12}{2} th \: term \\ \\ \sf{ \bold{ = > median}} = 6th \: term \\ \\ \sf{ \bold{ = > median}} = \orange{60}$

$\underline{ \boxed{ \rm{Hence \: the \: mean \: of \: the \: data \: is \: \bold{49.8182}}}}$

$\underline{ \boxed{ \rm{And \: the \: median \: of \: the \: data \: is \: \bold{60}}}}$

❖ Hope this helps you!

Answer 2

Answer:

Ans.

mode = 52

Median = 50

Mean=49.64

Step-by-step explanation:

The number of workers employed II month =

first we neet ascending order

40, 43, 45,47, 48,50, 52, 52, 53,56, 60

Add all the Number

so we get 52 and

Multiplay means we get 49.64

Subrat means = we get 50