The number of zeroes that polynomial f(x) = (x – 2)^2 + 4 can have is:
(i)1
(ii) 2
(iii) 0
(iv) 3
answer is zero.
plz tell why
Answers
Answered by
3
Step-by-step explanation:
ii} 2 Will be the answer
2 - 4
= 2
Answered by
2
Step-by-step explanation:
f(x) = (x – 2)^2 + 4
f(x)= x^2-4x+4+4
f(x)= x^2-4x+8
f(0)= 0^2-4*0+8
f(0)= 8
f(1)= 1^2-4*1+8
f(1)= 1-4+8
f(1)= 5
f(2)= 2^2-4*2+8
f(2)= 4-4+8
f(2)= 8
f(3)= 3^2-4*3+8
f(3)= 9-4+8
f(3)= 13
The number of zeroes that polynomial f(x) = (x – 2)^2 + 4 can have is:
iii) 0
because we put the value of x= 0,1,2,3,......
but the polynomial f(x) = (x – 2)^2 + 4 is not 0
so the zeros of that polynomial f(x) = (x – 2)^2 + 4 is 0 as we don't get the value zero for the polynomial at any value of x.
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