The number should be added to 6, 15, 20 and 43 to make the numbers
proportional is
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Let no. be ‘x’
∴ 6 + x/15 + x = 20 + x/43 + x
⇒ (6 + x)(43 + x) = (20 + x)(15 + x)
⇒ 258 + 49x + x2 = 300 + 35x + x2
⇒ 14x = 42
x = 3
∴ The required no is 3.
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