the number x is 2 more than the number y if the sum of the squares of x and y is 34 find the product of x and y
Answers
Answered by
28
x=y+2
x²+y²=34
(y+2)²+y²=34
y²+4+4y+y²=34
2y²+4y+4=34
y²+2y+2=17
y²+2y=15
y²+2y-15=0
y²+5y-3y-15=0
y(y+5)-3(y+5)=0
(y-3)(y+5)=0
∴ y=3
y= -5
x=y+2
1st case:
x=3+2
x=5
2nd case
x= -5+2
x= -3
x²+y²=34
(y+2)²+y²=34
y²+4+4y+y²=34
2y²+4y+4=34
y²+2y+2=17
y²+2y=15
y²+2y-15=0
y²+5y-3y-15=0
y(y+5)-3(y+5)=0
(y-3)(y+5)=0
∴ y=3
y= -5
x=y+2
1st case:
x=3+2
x=5
2nd case
x= -5+2
x= -3
Answered by
6
Answer:
15
Step-by-step explanation:
As given, x = y + 2 & x² + y² = 34
Case 1 :
⇒ x = y + 2
⇒ x - y = 2
Square on both sides:
⇒ (x - y)² = 2²
⇒ x² + y² - 2xy = 4
⇒ 34 - 2xy = 4
⇒ 34 - 4 = 2xy
⇒ 30/2 = xy
⇒ 15 = xy = product of x and y
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