Question

The numbers 1 to 12 inclusive are
placed in a hat. John takes a
number out of the bag at random.
What is the probability it is an odd

number?

Answer 1

$\pink { Number \:of \: total \: possible \: outcomes}$

$= Numbers \: placed \: in \:a \:hat$

$= 12 \: --(1)$

$Favourable\:outcomes$

$= \{ 1,3,5,7,9,11\}$

$\blue { Number \:of \: favourable \: outcomes} = 6\:--(2)$

$\orange { Probability ( an \:odd \: number )}$

$= \frac{(2)}{(1)}$

$= \frac{6}{12}$

$= \frac{1}{2}$

Therefore.,

$\red{ Probability ( an \:odd \: number )}\green { =\frac{1}{2}}$

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Answer 2

Given :

The numbers 1 to 12 inclusive are

placed in a hat. John takes a

number out of the bag at random.

To Find :

What is the probability it is an odd number?

Solution :

Total no. in hat = 12

_____________________

Favourable no. = 1,3,5,7,9,11

_____________________

no. of favourable no. in hat = 6

_____________________

probability of odd no. = 6/12

⇒ probability of odd no. = 1/2

☢ probability of odd no. is 1/2