The numbers 3446, 5887 and 2445 are put side by side in the same order making a 100 digits number. Find the remainder when this 100 digit number is divided by 9.
options:-(please answer fast as soon as possible)
1) 1
2)4
3)3
4)2
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Answer:
The numbers 3446, 5887 and 2445 are put side by side in the same order making a 100 digits number. The remainder when this 100 digit number is divided by 9 is 2
Step-by-step explanation:
When sum of digits of a number is divisible by 9 then number is divisible by 9.
if sum is 9a + b then remainder = b
344658872445
Sum of digits of 344658872445 = 60 ( 12 Digit)
to make 100 digits 12 digits will put aside 8 time then 4 digit of 3446
100 digit number would be
3446588724453446588724453446588724453446588724453446588724453446588724453446588724453446588724453446
Sum of digits = 60*8 + 17 = 497
497 = 55 * 9 + 2
so remainder = 2
option 4) - 2 is correct
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