Question

The numbers 3446, 5887 and 2445 are put side by side in the same order making a 100 digits number. Find the remainder when this 100 digit number is divided by 9.
options:-(please answer fast as soon as possible)
1) 1
2)4
3)3
4)2

Answer 1

Answer:

The numbers 3446, 5887 and 2445 are put side by side in the same order making a 100 digits number. The remainder when this 100 digit number is divided by 9  is 2

Step-by-step explanation:

When sum of digits of a number is divisible by 9 then number is divisible  by 9.

if sum is 9a + b then remainder = b

344658872445

Sum of digits of 344658872445 = 60  ( 12 Digit)

to make 100 digits 12 digits will put aside 8 time then 4 digit of 3446

100 digit number would be

3446588724453446588724453446588724453446588724453446588724453446588724453446588724453446588724453446

Sum of digits = 60*8 + 17 = 497

497 = 55 * 9 + 2

so remainder = 2

option 4)  -  2  is correct