Question

The numbers from 101 to 150 are written as, 101102103104105146147148149150. What will be the remainder when this total number is divided by 3?

Answer 1

Step-by-step explanation:

Answer 2

Given:

The numbers from 101 to 150 are written as, 101102103104105........146147148149150.

To find:

The remainder when this given number is divided by 3.

Solution:

1) It is given in the question that the number is divisible by the 3 and we know the divisibility rule of the 3 which states that the sum of the given number must be divisible by the 3.

2) So the sum of the digits of the given number must be divided by the 3 then the remainder left would be the remainder of the given number when divided by 3.

3) The sum of the digits of the given number is given by:

• 101+102+103+104+105........146+147+148+149+150

• (1+1+.......+1)50 times + 1+2+3.........+49+50

• 50+ 50×51/2

• 50+1275

• 1325

4) Now will divide 1325 with 3 and we get remainder as 2.

The remainder when this given number is divided by 3 is 2.