Question

The numbers of family members in ten families of
a locality are as follows:
4, 3, 2, 2, 5, 6, 7,3,3,5.
(a) Find the mean size of family member of the
above ten families
(b) How many families have their number of
members more than the average family size?​

Answer 1

Answer:

4

Step-by-step explanation:

Mean = Product of units and their frequencies divided by the sum of

             frequencies

Mean =  + 2*2=4        (as 2 is mentioned twice) 2 is the frequency

          + 3*3=9           (as 3 is mentioned thrice) 3 is the frequency

          + 4*1=4            (as 4 is mentioned once)  1 is the frequency

          + 5*2=10         (as 5 is mentioned twice)  2 is the frequency

          + 6*1=6           (as 6 is mentioned once)  1 is the frequency

          + 7*1=7           (as 7 is mentioned once)  1 is the frequency

          =4+9+4+10+6+7( Product of units and their frequencies) / 10 ( Sum of

             frequencies)

          =40/10

Mean =4

The mean size of the family is 4.

Since,4 families have their number of members more than the mean i.e

more than 4.        

         

Answer 2

The number of family members in ten families of a housing society are as follows:

4,3,2,2,5,6,7,3,3,5