Math, asked by sivagnanam53, 1 year ago

The numbers of Prime factors in 2^222 x 3^333 x 5^555 is
a.3 b.1107 c.1110 d.1272​

Answers

Answered by Gigendran
5

Answer:

C). 1110

Step-by-step explanation:

The number of prime factors in the given product

The number of prime factors in the given product= (222 + 333 + 555)

The number of prime factors in the given product= (222 + 333 + 555)= 1110

Answered by Abhijeet1589
0

The total number of prime factors is 1,110

GIVEN

Mathematical operation -

 {2}^{222}  \times  {3}^{333}  \times  {5}^{555}

TO FIND

The total number of prime factors.

SOLUTION

We can simply solve the above problem as follows-

We are given an expression -

 {2}^{222}  \times  {3}^{333}  \times  {5}^{555}

Let us expand every individual term;

 {2}^{222}  = 2 \times 2 \times 2........ \times 2

The above is expressed 222 times.

 {3}^{333}  = 3 \times 3 \times ..... \times3

The above term is expressed 333 times.

 {5}^{555}  = 5 \times 5 \times ..... \times 5

The above term is expressed 555 times.

Total number of prime factors = 222+333+555 = 1110

Hence, The total number of prime factors is 1,110

#spj2

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